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Chapter 12 Class 8 Factorisation Serial order wise Ex 12.2 Ex 12.2 Ex 12.2, 1 (i) Ex 12.2, 1 (ii) Ex 12.2, 1 (iii) Important Ex 12.2, 1 (iv) Important Ex 12.2, 1 (v) Ex 12.2, 1 (vi) Ex 12.2, 1 (vii) Important Ex 12.2, 1 (viii) Ex 12.2, 2 (i) Ex 12.2, 2 (ii) Important --> You are here Ex 12.2, 2 (iii) Ex 12.2, 2 (iv) Important Ex 12.2, 2 (v) Ex 12.2, 2 (vi) Ex 12.2, 2 (vii) Important Ex 12.2, 2 (viii) Important Ex 12.2, 3 (i) Ex 12.2, 3 (ii) Important Ex 12.2, 3 (iii) Ex 12.2, 3 (iv) Important Ex 12.2, 3 (v) Important Ex 12.2, 3 (vi) Ex 12.2, 3 (vii) Ex 12.2, 3 (viii) Important Ex 12.2, 3 (ix) Ex 12.2, 4 (i) Ex 12.2, 4 (ii) Important Ex 12.2, 4 (iii) Ex 12.2, 4 (iv) Important Ex 12.2, 4 (v) Important Ex 12.2, 5 (i) Ex 12.2, 5 (ii) Important Ex 12.2, 5 (iii) Ex 12.2, 2 (ii) - Chapter 12 Class 8 Factorisation Last updated at Dec. 16, 2024 by Transcript Ex 12.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^263𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((𝟑𝒂^𝟐 )−(𝟒𝒃)^𝟐 )Using 𝒙^𝟐−𝒚^𝟐=(𝑥+𝑦)(𝑥−𝑦)Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃) Chapter 12 Class 8 Factorisation Serial order wise Ex 12.2 Ex 12.2, 1 (i) Ex 12.2, 1 (ii) Ex 12.2, 1 (iii) Important Ex 12.2, 1 (iv) Important Ex 12.2, 1 (v) Ex 12.2, 1 (vi) Ex 12.2, 1 (vii) Important Ex 12.2, 1 (viii) Ex 12.2, 2 (i) Ex 12.2, 2 (ii) Important --> You are here Ex 12.2, 2 (iii) Ex 12.2, 2 (iv) Important Ex 12.2, 2 (v) Ex 12.2, 2 (vi) Ex 12.2, 2 (vii) Important Ex 12.2, 2 (viii) Important Ex 12.2, 3 (i) Ex 12.2, 3 (ii) Important Ex 12.2, 3 (iii) Ex 12.2, 3 (iv) Important Ex 12.2, 3 (v) Important Ex 12.2, 3 (vi) Ex 12.2, 3 (vii) Ex 12.2, 3 (viii) Important Ex 12.2, 3 (ix) Ex 12.2, 4 (i) Ex 12.2, 4 (ii) Important Ex 12.2, 4 (iii) Ex 12.2, 4 (iv) Important Ex 12.2, 4 (v) Important Ex 12.2, 5 (i) Ex 12.2, 5 (ii) Important Ex 12.2, 5 (iii) Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo. Canon zoombrowser; Zoombrowser ex 6 free; Zoom browser ex download; Zoombrowser 6.1 download; Zoombrowser ex download windows 7; Canon zoom browser; Canon zoombrowser download; Zoombrowser ex 5.5 software download; Zoombrowser ex windows 10 ZoomBrowser EX 6.4.1 Updater is software that will install ZoomBrowser EX 6.4.1 on your computer or update a previously installed version of ZoomBrowser EX to ZoomBrowser EX Double-click the [ZoomBrowser EX] shortcut icon on your desktop to start ZoomBrowser EX. If you cannot find the [ZoomBrowser EX] shortcut icon on your desktop, click [Start] ( ) [All Programs] or [Programs] [Canon Utilities] [ZoomBrowser EX] and select [ZoomBrowser EX] to start ZoomBrowser EX. ZoomBrowser EX 6.4.1 Updater is software that will install ZoomBrowser EX 6.4.1 on your computer or update a previously installed version of ZoomBrowser EX to ZoomBrowser Chapter 12 Class 8 Factorisation Serial order wise Ex 12.3 Ex 12.3 Ex 12.3, 1 (i) Ex 12.3, 1 (ii) Important Ex 12.3, 1 (iii) Ex 12.3, 1 (iv) Important Ex 12.3, 1 (v) Ex 12.3, 2 (i) Ex 12.3, 2 (ii) Important Ex 12.3, 2 (iii) Important Ex 12.3, 2 (iv) Ex 12.3, 2 (v) Important Ex 12.3, 3 (i) Ex 12.3, 3 (ii) Ex 12.3, 3 (iii) Important Ex 12.3, 3 (iv) Ex 12.3, 3 (v) Important --> You are here Ex 12.3, 4 (i) Ex 12.3, 4 (ii) Important Ex 12.3, 4 (iii) Ex 12.3, 4 (iv) Ex 12.3, 4 (v) Important Ex 12.3, 5 (i) Ex 12.3, 5 (ii) Important Ex 12.3, 5 (iii) Ex 12.3, 5 (iv) Important Ex 12.3, 5 (v) Ex 12.3, 5 (vi) Ex 12.3, 5 (vii) Important Ex 12.3, 3 (v) - Chapter 12 Class 8 Factorisation Last updated at Dec. 16, 2024 by Transcript Ex 12.3, 3 Work out the following divisions. (v) 96 abc (3a – 12) (5b – 30) ÷ 144 (a – 4) (b – 6)We first factorise96 abc (3a − 12) (5b − 30) = 96 abc (3a − (3 × 4)) (5b − 30)Taking 3 common, = 96 abc × 3 (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 5 × 6)Taking 5 common, = 288 abc (a − 4) × 5 (b − 6) = 288 × 5 abc (a − 4) (b − 6) = 1440 abc (a − 4) (b − 6)Dividing, (96 𝑎𝑏𝑐 (3𝑎 −12) (5𝑏 − 30))/(144 (𝑎 − 4) (𝑏 − 6)) = (1440 𝑎𝑏𝑐 (𝑎 − 4) (𝑏 − 6))/(144 (𝑎 − 4) (𝑏 − 6)) = 1440/144 × abc × ((𝑎 − 4))/((𝑎 − 4)) × ((𝑏 − 6))/((𝑏 − 6)) = 10 × abc × 1 × 1 = 10 abc Chapter 12 Class 8 Factorisation Serial order wise Ex 12.3 Ex 12.3, 1 (i) Ex 12.3, 1 (ii) Important Ex 12.3, 1 (iii) Ex 12.3, 1 (iv) Important Ex 12.3, 1 (v) Ex 12.3, 2 (i) Ex 12.3, 2 (ii) Important Ex 12.3, 2 (iii) Important Ex 12.3, 2 (iv) Ex 12.3, 2 (v) Important Ex 12.3, 3 (i) Ex 12.3, 3 (ii) Ex 12.3, 3 (iii) Important Ex 12.3, 3 (iv) Ex 12.3, 3 (v) Important --> You are

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Chapter 12 Class 8 Factorisation Serial order wise Ex 12.2 Ex 12.2 Ex 12.2, 1 (i) Ex 12.2, 1 (ii) Ex 12.2, 1 (iii) Important Ex 12.2, 1 (iv) Important Ex 12.2, 1 (v) Ex 12.2, 1 (vi) Ex 12.2, 1 (vii) Important Ex 12.2, 1 (viii) Ex 12.2, 2 (i) Ex 12.2, 2 (ii) Important --> You are here Ex 12.2, 2 (iii) Ex 12.2, 2 (iv) Important Ex 12.2, 2 (v) Ex 12.2, 2 (vi) Ex 12.2, 2 (vii) Important Ex 12.2, 2 (viii) Important Ex 12.2, 3 (i) Ex 12.2, 3 (ii) Important Ex 12.2, 3 (iii) Ex 12.2, 3 (iv) Important Ex 12.2, 3 (v) Important Ex 12.2, 3 (vi) Ex 12.2, 3 (vii) Ex 12.2, 3 (viii) Important Ex 12.2, 3 (ix) Ex 12.2, 4 (i) Ex 12.2, 4 (ii) Important Ex 12.2, 4 (iii) Ex 12.2, 4 (iv) Important Ex 12.2, 4 (v) Important Ex 12.2, 5 (i) Ex 12.2, 5 (ii) Important Ex 12.2, 5 (iii) Ex 12.2, 2 (ii) - Chapter 12 Class 8 Factorisation Last updated at Dec. 16, 2024 by Transcript Ex 12.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^263𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((𝟑𝒂^𝟐 )−(𝟒𝒃)^𝟐 )Using 𝒙^𝟐−𝒚^𝟐=(𝑥+𝑦)(𝑥−𝑦)Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃) Chapter 12 Class 8 Factorisation Serial order wise Ex 12.2 Ex 12.2, 1 (i) Ex 12.2, 1 (ii) Ex 12.2, 1 (iii) Important Ex 12.2, 1 (iv) Important Ex 12.2, 1 (v) Ex 12.2, 1 (vi) Ex 12.2, 1 (vii) Important Ex 12.2, 1 (viii) Ex 12.2, 2 (i) Ex 12.2, 2 (ii) Important --> You are here Ex 12.2, 2 (iii) Ex 12.2, 2 (iv) Important Ex 12.2, 2 (v) Ex 12.2, 2 (vi) Ex 12.2, 2 (vii) Important Ex 12.2, 2 (viii) Important Ex 12.2, 3 (i) Ex 12.2, 3 (ii) Important Ex 12.2, 3 (iii) Ex 12.2, 3 (iv) Important Ex 12.2, 3 (v) Important Ex 12.2, 3 (vi) Ex 12.2, 3 (vii) Ex 12.2, 3 (viii) Important Ex 12.2, 3 (ix) Ex 12.2, 4 (i) Ex 12.2, 4 (ii) Important Ex 12.2, 4 (iii) Ex 12.2, 4 (iv) Important Ex 12.2, 4 (v) Important Ex 12.2, 5 (i) Ex 12.2, 5 (ii) Important Ex 12.2, 5 (iii) Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

2025-04-03
User1096

Chapter 12 Class 8 Factorisation Serial order wise Ex 12.3 Ex 12.3 Ex 12.3, 1 (i) Ex 12.3, 1 (ii) Important Ex 12.3, 1 (iii) Ex 12.3, 1 (iv) Important Ex 12.3, 1 (v) Ex 12.3, 2 (i) Ex 12.3, 2 (ii) Important Ex 12.3, 2 (iii) Important Ex 12.3, 2 (iv) Ex 12.3, 2 (v) Important Ex 12.3, 3 (i) Ex 12.3, 3 (ii) Ex 12.3, 3 (iii) Important Ex 12.3, 3 (iv) Ex 12.3, 3 (v) Important --> You are here Ex 12.3, 4 (i) Ex 12.3, 4 (ii) Important Ex 12.3, 4 (iii) Ex 12.3, 4 (iv) Ex 12.3, 4 (v) Important Ex 12.3, 5 (i) Ex 12.3, 5 (ii) Important Ex 12.3, 5 (iii) Ex 12.3, 5 (iv) Important Ex 12.3, 5 (v) Ex 12.3, 5 (vi) Ex 12.3, 5 (vii) Important Ex 12.3, 3 (v) - Chapter 12 Class 8 Factorisation Last updated at Dec. 16, 2024 by Transcript Ex 12.3, 3 Work out the following divisions. (v) 96 abc (3a – 12) (5b – 30) ÷ 144 (a – 4) (b – 6)We first factorise96 abc (3a − 12) (5b − 30) = 96 abc (3a − (3 × 4)) (5b − 30)Taking 3 common, = 96 abc × 3 (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 5 × 6)Taking 5 common, = 288 abc (a − 4) × 5 (b − 6) = 288 × 5 abc (a − 4) (b − 6) = 1440 abc (a − 4) (b − 6)Dividing, (96 𝑎𝑏𝑐 (3𝑎 −12) (5𝑏 − 30))/(144 (𝑎 − 4) (𝑏 − 6)) = (1440 𝑎𝑏𝑐 (𝑎 − 4) (𝑏 − 6))/(144 (𝑎 − 4) (𝑏 − 6)) = 1440/144 × abc × ((𝑎 − 4))/((𝑎 − 4)) × ((𝑏 − 6))/((𝑏 − 6)) = 10 × abc × 1 × 1 = 10 abc Chapter 12 Class 8 Factorisation Serial order wise Ex 12.3 Ex 12.3, 1 (i) Ex 12.3, 1 (ii) Important Ex 12.3, 1 (iii) Ex 12.3, 1 (iv) Important Ex 12.3, 1 (v) Ex 12.3, 2 (i) Ex 12.3, 2 (ii) Important Ex 12.3, 2 (iii) Important Ex 12.3, 2 (iv) Ex 12.3, 2 (v) Important Ex 12.3, 3 (i) Ex 12.3, 3 (ii) Ex 12.3, 3 (iii) Important Ex 12.3, 3 (iv) Ex 12.3, 3 (v) Important --> You are

2025-04-10
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2025-03-29
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NM EX VG G NM EX VG G NM EX VG G NM EX VG G NM EX VG G Edward Kenway (0143 - Showcase) 5/5 Legendary Creature - Human Assassin Pirate At the beginning of your end step, create a Treasure token for each tapped Assassin, Pirate, and/or Vehicle you control.Whenever a Vehicle you control deals combat damage to a player, look at the top card of that player's library, then exile it face down. You may play that card for as long as it remains exiled. NM EX VG G NM EX VG G NM EX VG G NM EX VG G NM EX VG G Mjolnir, Storm Hammer (0170 - Extended Art) Legendary Artifact - Equipment When Mjolnir enters the battlefield, attach it to target legendary creature you control.Whenever equipped creature attacks, tap target creature defending player controls and put a stun counter on it. Then Mjolnir deals damage to each opponent equal to the number of tapped creatures that opponent controls.Equip NM EX VG G NM EX VG G NM EX VG G NM EX VG G Altair Ibn-La'Ahad (0137 - Showcase) 3/3 Legendary Creature - Human Assassin First strikeWhenever Altair Ibn-La'Ahad attacks, exile up to one target Assassin creature card from your graveyard with a memory counter on it. Then for each creature card you own in exile with a memory counter on it, create a tapped and attacking token that's a copy of it. Exile those tokens at end of combat. NM EX VG G NM EX VG G NM EX VG G NM EX VG G NM EX VG G NM EX VG G NM EX VG G Kassandra, Eagle Bearer (0148 - Showcase) 2/2 Legendary Creature - Human Assassin Warrior HasteWhen Kassandra enters the battlefield, search your graveyard, hand, and library for a card named The Spear of Leonidas, put it onto the battlefield, then shuffle.Whenever a creature you control with a legendary Equipment attached to it deals combat damage to a player, draw a card. NM EX VG G NM EX VG G NM EX VG G

2025-04-11
User8292

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2025-04-24
User9200

Dear Rusty: If a financially well-off individual had multiple ex-spouses, could it happen that the multiple ex-spouses could each be collecting Social Security based on their own financial situation as compared to their rich ex-spouses? Thus, multiple payouts by SS? Just curious, because there are probably many people in this situation as a result of the ever-increasing number of people involved in multiple marriages that each lasted more than ten years. Signed: Curious Ex-SpouseDear Curious Ex-Spouse: A former spouse can only collect one SS benefit – either their own SS retirement amount, or an amount as an ex-spouse if the marriage lasted 10 years or more. And it is possible for multiple ex-spouses of a marriage to the same person to qualify for benefits from those unions, if each marriage lasted at least 10 years. But each ex-spouse can only qualify for one benefit payment – either their own earned SS benefit, or their benefit as an ex-spouse. In other words, someone with two (or more) ex-spouses might have their ex’s collecting full benefits on their record, provided that each marriage lasted at least 10 years. But an ex-spouse can only get one benefit –their own SS retirement amount or an ex-spouse amount – whichever is higher).It’s possible, also, that an ex-spouse can collect benefits from a former spouse at the same time as a current spouse is also collecting spouse benefits on the same record. And there is no detriment to either’s amount because multiple spouses or ex-spouses are collecting on a one person’s SS record (Social Security is, after all, a means for spouses, or ex-spouses, to avoid poverty). However, an ex-spouse’s own SS retirement benefit (from their personal lifetime work record) must be less than any ex-spouse benefit they are entitled to from a former spouse. Essentially, if the “10-years-married” rule is satisfied, ex-spouses are subject to the same benefit rules as a current spouse.You are correct that we see some cases like this these days, but each eligible ex-spouse can only get one benefit, and their ex-spouse benefit is always offset by any personal SS retirement benefit the ex-spouse may also be entitled to on their own lifetime work record.

2025-03-27

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