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HBot is currently down due to some bug with Magick(dot)NET that's causing CPU/memory leaks. Using wix, how to install Dot net framework 4.5 for Windows 7/8 and dot net 4.0 from Xp and vista. 4. Install .net 4.6.2 with Wix 3.10. 4. Detect .Net 4.7 with Wix Installer 3.11.

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AAI AAI AAI Dune image APNG APNG Animated Portable Network Graphics ART ART PFS: 1st Publisher AVI AVI Microsoft Audio/Visual Interleaved AVS AVS AVS X image BAYER BAYER Raw mosaiced samples BPG BPG Better Portable Graphics BRF BRF Braille Ready Format CALS CALS Continuous Acquisition and Life-cycle Support Type 1 image CIN CIN Kodak Cineon Image Format CMYK CMYK Raw cyan, magenta, yellow, and black samples CMYKA CMYKA Raw cyan, magenta, yellow, black, and alpha samples CUBE CUBE Cube Color lookup table converted to a HALD image CUR CUR Microsoft Cursor Icon CUT CUT DR Halo DCM DCM/DICOM Digital Imaging and Communications in Medicine (DICOM) image DCX DCX ZSoft IBM PC multi-page Paintbrush image DDS DDS Microsoft Direct Draw Surface DIB DIB Microsoft Windows Device Independent Bitmap DOT DOT Graph Visualization DPX DPX SMPTE Digital Moving Picture Exchange EMF EMF Microsoft Enhanced Metafile (32-bit) EPDF EPDF Encapsulated Portable Document Format EPI EPI Adobe Encapsulated PostScript Interchange format (requires Ghostscript to read) EPS2 EPS2 Adobe Level II Encapsulated PostScript (requires Ghostscript to read) EPS3 EPS3 Adobe Level III Encapsulated PostScript (requires Ghostscript to read) EPSF EPSF Adobe Encapsulated PostScript (requires Ghostscript to read) EPSI EPSI Adobe Encapsulated PostScript Interchange format (requires Ghostscript to read) EPT EPT Adobe Encapsulated PostScript Interchange format with TIFF preview (requires Ghostscript to read) EXR EXR High dynamic-range (HDR) file format developed by Industrial Light & Magic FARBFELD FARBFELD Farbfeld lossless image format FAX FAX Group 3 TIFF FITS FITS Flexible Image Transport System FL32 FL32 FilmLight floating point image format FLIF FLIF Free Lossless Image Format FPX FPX FlashPix Format FTXT FTXT Read and write multispectral channels as formatted text GRAY GRAY Raw gray samples GRAYA GRAYA Raw gray and alpha samples HDR HDR Radiance RGBE image format HRZ HRZ Slow Scan TeleVision ICO ICO/ICON Microsoft icon INFO INFO Format and characteristics of the image INLINE INLINE Base64-encoded inline image JBIG JBIG/BIE/JBG Joint Bi-level Image experts Group file interchange format JNG JNG Multiple-image Network Graphics JSON JSON JavaScript Object Notation, a lightweight data-interchange format JXL JXL JPEG XL image coding system KERNEL KERNEL Morphology kernel format MAT MAT MATLAB image format MIFF MIFF Magick image file format MONO MONO Bi-level bitmap in least-significant-byte first order MNG MNG Multiple-image Network Graphics MPC MPC Magick Persistent Cache image file format MSL MSL/MS Magick Scripting Language MTV MTV MTV Raytracing image format MVG MVG Magick Vector Graphics ORA ORA Open exchange format for layered raster based graphics OTB OTB On-the-air Bitmap P7 P7 Xv's Visual Schnauzer thumbnail format PALM PALM Palm pixmap PAM PAM Common 2-dimensional bitmap format CLIPBOARD CLIPBOARD Windows Clipboard (only for Windows) PBM PBM Portable bitmap format (black and white) PCD PCD Photo CD PCDS PCDS

HBot is currently down due to some bug with Magick(dot)NET

Thus the RCM constraint can be satisfied and modulated by resolving the joint angle variable \(\theta \).4 Simplified RNN for Redundancy Resolution with RCM ConstraintsIn this section, the modeling and theoretical analysis of the proposed SIMPLIFIED RNN for redundancy resolution with RCM constraints are addressed.4.1 Optimization ParadigmIn order to deal with the RCM constrained redundancy resolution issue, in this work, Lagrange function which is simultaneously associated with the kinematic objective function and the RCM constraint is defined as follows$$\begin{aligned} \begin{aligned} L=&\dot{\theta }^T\dot{\theta }/2+c_2\dot{k}^2/2+\lambda _1^T[\dot{k}(r_A-r_B)+kJ_1\dot{\theta }+(1-k)J_2\dot{\theta }\\&+c_1(r_P-r_P(0))]+\lambda _2^T[J_1{\dot{\theta }}+c_3(r_A-r_d)-\dot{r}_d] \end{aligned} \end{aligned}$$ (10) where \(\lambda _1\) and \(\lambda _2\) denote the Lagrange multiplier vectors. The partial derivatives of the Lagrange function with respect to the unknown variables \(({\dot{\theta }},\dot{k},\lambda _1,\lambda _2)\) are$$\begin{aligned} \left\{ \begin{array}{ll} \frac{\partial L}{\partial {\dot{\theta }}}={\dot{\theta }}+[kJ_1+(1-k)J_2]^T\lambda _{1}+J_1^T\lambda _2\\ \frac{\partial L}{\partial \dot{k}}=c_2\dot{k}+ \lambda _{1}^T(r_A-r_B)\\ \frac{\partial L}{\partial \lambda _{1}}=(kJ_1+(1-k)J_2)\dot{\theta }+\dot{k}(r_A-r_B)\\ ~~~~~~~+c_1(r_P-r_P(0))\\ \frac{\partial L}{\partial \lambda _{2}}=J_1{\dot{\theta }}+c_3(r_A-r_d)-\dot{r}_d \end{array} \right. \end{aligned}$$ (11) According to the Karush-Kuhn-Tucker (KKT) conditions [25] , the optimization above can be solved by force the following equations$$\begin{aligned} \left\{ \begin{array}{ll} \frac{\partial L}{\partial {\dot{\theta }}}=0\\ \frac{\partial L}{\partial \dot{k}}=0\\ \frac{\partial L}{\partial \lambda _{1}}=0\\ \frac{\partial L}{\partial \lambda _{2}}=0 \end{array} \right. \end{aligned}$$ (12) to be zero and obtain the desired solution \(({\dot{\theta }}^*,\dot{k}^*,\lambda _1^*,\lambda _2^*)\) for satisfying the optimization objective and constraints.4.2 Original ZD-based RNN MethodIn order to solve such optimization paradigm which reflects the redundancy resolution with RCM constraints, according to the general design principle of the ZD-based RNN model to make the aforementioned partial derivatives of the Lagrange function being 0, we thus need to construct the following error-monitoring function$$\begin{aligned} \begin{aligned} \Xi&=\begin{bmatrix} {\dot{\theta }}+[kJ_1+(1-k)J_2]^T\lambda _{1}+J_1^T\lambda _2\\ c_2\dot{k}+ \lambda _{1}^T(r_A-r_B)\\ (kJ_1+(1-k)J_2)\dot{\theta }+\dot{k}(r_A-r_B)+c_1(r_P-r_P(0))\\ J_1{\dot{\theta }}+c_3(r_A-r_d)-\dot{r}_d \end{bmatrix}\\&=AZ+B \end{aligned} \end{aligned}$$ (13) where$$\begin{aligned} A= & {} \begin{bmatrix} I_{n\times n} &{} 0_{n\times 1} &{} kJ_1^T+(1-k)J_2^T &{} J_1^T\\ 0 &{} c_2 &{} r_A^T-r_B^T &{} 0_{1\times m} \\ kJ_1+(1-k)J_2 &{} r_A-r_B &{} 0 &{} 0 \\ J_1 &{} 0_{m\times 1} &{} 0 &{} 0 \end{bmatrix} \end{aligned}$$ (14) $$\begin{aligned} Z= & {} \begin{bmatrix} {\dot{\theta }}\\ \dot{k}\\ \lambda _1\\ \lambda _2 \end{bmatrix}~~\text {and}~~B=\begin{bmatrix} 0_{n\times 1}\\ 0\\ 0_{m\times 1}\\ c_3(r_A-r_d)-\dot{r}_d \end{bmatrix} \end{aligned}$$ (15) Our goal of applying ZD-based method is to force \(\varXi =0\) eventually and thus the resultant optimal solution of Z can be got.Based on the design discipline of the ZD method, we have the following error-processing formula for redundancy resolution of manipulator with RCM constraints$$\begin{aligned} \dot{\varXi }=-\gamma \varPsi (\varXi ) \end{aligned}$$ (16) where the convergence scaling parameters can be configured as \(\gamma >0\) for unity, \(\varPsi (\cdot ):R^{(n+7)\times (n+7)}\rightarrow R^{(n+7)\times (n+7)}\) denotes the general nonlinear activation function array with its entries being monotonously-increasing odd functions. Therefore, we would have the following ZD-based neural network model for redundancy resolution of manipulator with RCM constraints$$\begin{aligned} \dot{A}Z+A\dot{Z}+\dot{B}=-\gamma \varPsi (AZ+B) \end{aligned}$$ (17) Due to existence of time derivative of coefficient matrix A in the system equation above, such ZD model needs to obtain the time-derivatives of Jacobian matrices analytically during its solution to update the model states,i.e., the coefficient matrix \(\dot{A}\) that is consisted of Jacobian matrices \(\dot{J}_1\) and \(\dot{J}_2\). However, the analytical time-derivative

Magick: ImageMagick-7/Magick/lib/Magick/Include.h

Despite a 23-point road victory, the Boise State men’s basketball team still took a hit in the NCAA NET Rankings. The Broncos (22-8, 14-5) had no issues with Air Force (4-26, 1-18) in Tuesday’s Mountain West Conference game, cruising to a comfortable 80-57 win. It was Boise State’s fifth straight victory and ninth in its last 10 games.The metrics weren’t impressed with the performance as the Broncos fell three spots to No. 45 in the NET Rankings. Air Force is the MWC’s lowest NET team at No. 317. Boise State, an NCAA Tournament bubble team, holds a 3-5 record in Quad 1 games. The Broncos are much better in Quad 2 at 4-1.Utah State (24-6, 14-5) is the top MWC in the NET at No. 40. The Aggies have dropped two straight games entering Saturday’s 2 p.m. Mountain time regular-season finale against Air Force. New Mexico (24-6, 16-3), which earned a hard-fought 71-67 road victory at Nevada (16-14, 8-11) Tuesday night to clinch the MWC regular-season title, is next in the NET at No. 44. Boise State is third at No. 45, followed by No. 52 San Diego State (20-8, 13-6) and No. 56 Colorado State (21-9, 15-4). The winner of Friday’s 8 p.m. matchup between the Broncos and Rams at ExtraMile Arena will clinch the No. 2 seed for the MWC Tournament. Here is a closer look at each Mountain West member’s NCAA Tournament resume through the lens of the NET Rankings.NET Ranking: 40Record: 24-6, 14-5 Q1: 3-3 Q2: 7-3 Q3: 4-0 Q4: 9-0NET Ranking: 44Record: 24-6, 16-3 Q1: 5-3 Q2: 7-1 Q3: 1-2 Q4: 10-0NET Ranking: 45Record: 22-8, 14-5 Q1: 3-5 Q2: 4-1 Q3: 4-2 Q4: 10-0NET Ranking: 52Record: 20-8, 13-6 Q1: 4-5 Q2: 4-2 Q3: 3-1 Q4: 8-0NET Ranking: 56Record: 21-9, 15-4 Q1: 1-5 Q2: 6-2 Q3: 3-2 Q4: 11-0NET Ranking: 74Record: 16-14, 8-11 Q1: 1-5 Q2: 2-6 Q3: 4-3 Q4: 9-0NET Ranking: 93Record: 17-13, 11-8 Q1: 1-7 Q2: 3-5 Q3: 4-0 Q4: 9-1NET Ranking: 188Record: 13-18, 6-13 Q1: 0-7 Q2: 1-6 Q3: 4-3 Q4: 6-2NET Ranking: 194Record: 12-19, 5-15 Q1: 0-8 Q2: 2-5 Q3: 1-4 Q4: 8-2NET Ranking: 274Record: 6-24, 2-17 Q1: 0-8 Q2: 0-7 Q3: 0-5 Q4: 6-4NET Ranking: 317Record: 4-26, 1-18 Q1: 0-5 Q2: 0-9 Q3: 1-7 Q4: 3-5MORE BOISE STATE NEWS & ANALYSISFOLLOW US ON SOCIAL MEDIAContinue to follow our Boise State coverage on social media by liking us on Facebook and following us on Twitter.. HBot is currently down due to some bug with Magick(dot)NET that's causing CPU/memory leaks. Using wix, how to install Dot net framework 4.5 for Windows 7/8 and dot net 4.0 from Xp and vista. 4. Install .net 4.6.2 with Wix 3.10. 4. Detect .Net 4.7 with Wix Installer 3.11.

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After 11 overs Over summary: 0 2 1 0 0 0; India 67/1 after 11 overs; Shubman Gill 35 (38), Virat Kohli 9 (13) Partnership: 36 (36) India need 175 runs to win in 39 overs Haris Rauf comes into the attack. Ball 6- Dot ball Ball 5- Play and a miss for Gill Ball 4- Dropped. Rauf is scratching his head as Khushdil drops in-form Gill. How costly will be this for Pakistan Ball 3- Kohli takes a single to backward point Ball 2- Kohli takes two runs to square leg Ball 1- Dot ball7:38 PMIND vs PAK LIVE SCORE UPDATES: Batting powerplay concludes Over summary: 0 0 0 0 1 0; India 64/1 after 10 overs; Shubman Gill 35 (35), Virat Kohli 6 (10) Partnership: 33 (30) India need 178 runs to win in 40 overs Naseem continues the attack. Ball 6- Dot ball Ball 5- Kohli put the ball to mid off and steals a quick single Ball 4- Kohli drives the ball to man at mid-wicket for no run Ball 3- Kohli defends on backfoot Ball 2- Kohli with full defence. No run Ball 1- Kohli plays the ball to mid wicket for no run7:34 PMIND vs PAK LIVE SCORE UPDATES: 50 up for India Over summary: 2 1Wd 4 0 0 4 2; India 63/1 after 9 overs; Shubman Gill 35 (34), Virat Kohli 5 (5) Partnership: 32 (24) India need 179 runs to win in 41 overs Afridi continues the attack. Ball 6- Gill flicks the ball to backward square leg for two runs Ball 5- Gill goes down the ground and sends the ball over bowlers head to long on for four runs Ball 4- Gill punches the ball to mid-off for no run Ball 3- Dot ball Ball 2- Gill just drives the ball to extra cover for four runs Ball 2- 2 WIDE Ball 1- Kohli flicks the ball to backward square leg for two runs7:29 PMIND vs PAK LIVE SCORE UPDATES: 3 runs from the over Over summary: 0 2 0 1 0 0; India 49/1 after 8 overs; Shubman Gill 25 (29), Virat Kohli 3 (4)Partnership: 18 (18)India need 193 runs to win in 42 overs Naseem continues the attack. Ball 6- Dot ball Ball 5- Dot ball Ball 4- Kohli takes a single to mid off Ball 3- Kohli just blocks the ball Ball 2- Kohli opens his account with two runs to backward square leg Ball 1- Kohli defends the ball for no run7:24 PMIND vs PAK LIVE SCORE UPDATES: Gill witth the counter attack Over summary: 2 4 0 4 4 0; India 46/1 after 7 overs; Shubman Gill 25 (27), Virat Kohli 0 (0)Partnership: 15 (12)India need 196 runs to win in 43 overs Afridi continues the attack. Ball 6- Dot ball Ball 5- Back-to-back boundaries for Gill Ball 4- Gill gets four runs to square leg Ball 3- Dot ball Ball 2- Gill jabs the ball to deep mid wicket for four runs Ball

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\(k=0\) is configured, then \(r_P=r_B\); when \(k=1\) is configured, then \(r_P=r_A\); when \(0, \(r_P\) is strictly between points \(r_A\) and \(r_B\). The redundancy resolution for kinematic control of the manipulator needs to finish the two tasks, 1) let the end-effector track the desired path accurately; and 2) satisfy the RCM constraint to make \(r_P\) vary in a very small range or almost static during motion planning and control. In an application scenario, the last link (e.g., \(r_A-r_B\)) of the manipulator can penetrate a small hole (e.g., \(r_P\)) and simultaneously make the end-effector (e.g., \(r_A\)) perform the path tracking task.3 Problem FormulationAs the RCM constraint makes point \(r_P\) is between \(r_A\) and \(r_B\), \(r_P\) can be depicted by the equation \(r_p-r_B=k(r_A-r_B)\). Since \(r_A\) and \(r_B\) are obtained through the forward kinematics with resolved joint angles \(\theta \), thus the state variable pair \((\theta , k)\) can describe the redundancy resolution of the manipulator with RCM constraints. By differentiating the both sides of equation \(r_p-r_B=k(r_A-r_B)\) which depicts the RCM constraint, one can obtain$$\begin{aligned} \dot{r}_P-\dot{r}_B=\dot{k}(r_A-r_B)+k(\dot{r}_A-\dot{r}_B) \end{aligned}$$ (3) When combining it with the aforementioned Eq. (1), one can further have$$\begin{aligned} \dot{r}_P-J_2\dot{\theta }=\dot{k}(r_A-r_B)+k(J_1-J_2)\dot{\theta } \end{aligned}$$ (4) As the position of RCM point \(r_P\) can be described by the following linear combination between \(r_A\) and \(r_B\)$$\begin{aligned} r_P=k(r_A-r_B)+r_B \end{aligned}$$ (5) Combining the aforementioned equations, then we have$$\begin{aligned} \dot{k}(r_A-r_B)+kJ_1\dot{\theta }+(1-k)J_2\dot{\theta }+\dot{r}_P=0 \end{aligned}$$ (6) i.e.,$$\begin{aligned} \begin{aligned} \dot{k}(r_A-r_B)+[kJ_1+(1-k)J_2]\dot{\theta }+\dot{r}_P=0 \end{aligned} \end{aligned}$$ (7) where we can call the equality above as the RCM constraint for redundancy resolution.Based on the derivations and discussions above, we propose the quadratic programming formulation for redundancy resolution of manipulators with RCM constraints as follows$$\begin{aligned} \begin{aligned}&\arg \min _{\theta ,k}~~\dot{\theta }^T\dot{\theta }/2+c_2\dot{k}^2/2\\&\text {s.t.}\left\{ \begin{array}{ll} \dot{k}(r_A-r_B)+[kJ_1+(1-k)J_2]\dot{\theta }+\dot{r}_P=0\\ J_1\dot{\theta }+c_3(r_A-r_d)-\dot{r}_d=0 \end{array} \right. \end{aligned} \end{aligned}$$ (8) where \(c_2>0\) and \(c_3>0\) denote the scaling parameters for the objective function and the last equality constraint respectively. In order to satisfy RCM constraints during redundancy resolution for kinematic control, the time-derivative \(\dot{r}_P\) of \(r_P\) should follow some rules to make \(r_P\) converge to a constant position value.As the point \(r_P\) should not hold static as much as possible to sanctify the RCM constraint, then the time derivative of \(r_P\) can be concisely depicted by$$\begin{aligned} \dot{r}_P=-c_1(r_P-r_P(0)) \end{aligned}$$ (9) to make the RCM point \(r_P\) converge to a fixed position \(r_P(0)\), where \(c_1\ge 0\) is used to scale the convergence of \(r_P\) which shows how the corresponding RCM constraint’s dynamic response changes.In the proposed optimization formulation for redundancy resolution with RCM constraints, the position of \(r_P\) is dynamically adjusted by parameter k with simultaneous positions \(r_A\) and \(r_B\). The initial value k(0) is chosen according to the specific scenarios for safe manipulation, e.g., when \(t=0\), \(r_P\) can be chosen in the middle of the line \(A-B\), and thus \(k(0)=0.5\). To maintain the RCM constraint, \({\dot{\theta }}\) and \(\dot{k}\) are used as decision variables, and the variable which really controls the manipulator is \(\dot{\theta }\) as the control input action. In practice, we can therefore solve \(\dot{k}\) and substitute it into the aforementioned proposed optimization formulation and

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We have just released .NET Reflector 7 0 votes 0 comments Update experience 0 votes 0 comments Remove the gold plating 0 votes 0 comments **.NET Reflector 7 Beta 5 Now Available** 0 votes 0 comments Expiry 0 votes 1 comment Clicking Open in Reflect kills DevStudio 2010 0 votes 2 comments Disassembler fails if you are not running under elevated use 0 votes 6 comments Decompie event 0 votes 1 comment Invalid object initializer generated in C# and VB.NET 0 votes 0 comments Unexpected character $ in generated C# file 0 votes 2 comments Unable to open project properties on generated .csproj file 0 votes 15 comments Beta 4 0 votes 1 comment **.NET Reflector 7 Beta 4 Now Available** 0 votes 0 comments Pointers 0 votes 1 comment Missing single assembly refresh action 0 votes 1 comment Invalid C# statement 0 votes 1 comment Can't activate Pro version 0 votes 1 comment **.NET Reflector 7 Beta 3 Now Available** 0 votes 0 comments IEnumerable<> issue 0 votes 0 comments Private method access - wrong 0 votes 4 comments Mono support! 0 votes 1 comment Incomplete export 0 votes 1 comment Cast not valid issue 0 votes 0 comments foreach nevereding loop issue 0 votes 6 comments missing using directive 0 votes 3 comments Pointers support 0 votes 2 comments Operator ++ 0 votes 1 comment Decompilation problem 0 votes 1 comment .resources display 0 votes 0 comments CTRL+F4 can't close opened assembly 0 votes 0 comments. HBot is currently down due to some bug with Magick(dot)NET that's causing CPU/memory leaks. Using wix, how to install Dot net framework 4.5 for Windows 7/8 and dot net 4.0 from Xp and vista. 4. Install .net 4.6.2 with Wix 3.10. 4. Detect .Net 4.7 with Wix Installer 3.11.

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I have a web app that has a file upload form with an end goal of saving the uploaded file as a jpeg when the filetype is heic.Because System.Drawing.Imaging does NOT support heic, and it appears Magick does (possible HEIC requires the libheif delegate library.) not sure how you would do this in a C# or VB.Net web app, or if I actually need the library for converting a uploaded file from HEIC to Jpeg.What I am doing now is taking the uploaded file, convert to Byte() then put in a MemoryStream, then try and MagickImage it with a settings file where I tell Magick that the in file format is heic. ( had to specify the format to get past the "no decode delegate for this image format `' @ error/blob.c/BlobToImage/458" error).Now I get a "Invalid input: No 'ftyp' box `' @ error/heic.c/IsHeifSuccess/134" which searching the Magick github I see no code reference to ftpy, but when I search the library that magick says is required, I do see references to this. But the libheif seems to be only c++ code, and have no clue how to use that library in a .NET web app.Here is the code I am using to try and convert the heic byte data to jpeg byte data. Error occurs at the MagickImage line.VB Dim DataBytes As Byte() Dim settings As MagickReadSettings = New MagickReadSettings() settings.Format = MagickFormat.Heic Using m As MemoryStream = New MemoryStream() Using image As MagickImage = New MagickImage(heicfile, settings) image.Format

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Virat Kohli hits 51st ODI century7:59 PMIND vs PAK LIVE SCORE UPDATES: India 93 for 1 after 16 overs Over summary: 2 0 0 0 1 1; India 93/1 after 16 overs; Shubman Gill 43 (47), Virat Kohli 27 (34) Partnership: 62 (66) India need 149 runs to win in 34 overs Abrar continues the attack. Ball 6- Ball 5- Kohli plays athe ball to cover for a single Ball 4- Dot ball Ball 3- Dot ball Ball 2- Dot ball Ball 1- Kohli starts the over with two runs7:57 PMIND vs PAK LIVE SCORE UPDATES: India 89 for 1 after 15 overs Over summary: 1 0 0 0 0 1; India 89/1 after 15 overs; Shubman Gill 42 (46), Virat Kohli 24 (29) Partnership: 56 (54) India need 153 runs to win in 35 overs Khushdil comes in the attack. Ball 6- Kohli keeps the strike with a single Ball 5- Kohli is failing to find gap. No run Ball 4- Dot ball again Ball 3- Kohli tries to setal a quick single. Gill refuses. No run Ball 2- Dot ball Ball 1- Gill takes a single to long off7:54 PMIND vs PAK LIVE SCORE UPDATES: India 87 for 1 after 14 overs Over summary: 1 1 1 0 0 0; India 87/1 after 14 overs; Shubman Gill 41 (45), Virat Kohli 23 (24) Partnership: 56 (54) India need 155 runs to win in 36 overs Abrar continues the attack. Ball 6- Dot ball Ball 5- Dot Ball Ball 4- Dot ball Ball 3- Gil;l takes a single to deep square leg Ball 2- Kohli takes a single to deep mid-wicket Ball 1- Gill takes a single to long on7:51 PMIND vs PAK LIVE SCORE UPDATES: India 84 for 1 after 13 overs Over summary: 2 4 1 3 0 4; India 84/1 after 13 overs; Shubman Gill 39 (43), Virat Kohli 22 (20) Partnership: 53 (48) India need 158 runs to win in 33 overs Rauf continues the attack. Ball 6- Kohli collects four more with cover drive Ball 5- Dot ball Ball 4- Gill takes three runs to mid wicket Ball 3- Kohli takes a single to cover point Ball 2- Kohli gets four to long on and compltes the much anticipated milestone of 14000 ODI runs Ball 1- Kohli takes two runs to cover7:47 PMIND vs PAK LIVE SCORE UPDATES: India 70 for 1 after 12 overs Over summary: 1 0 0 0 1 1; India 70/1 after 12 overs; Shubman Gill 36 (42), Virat Kohli 11 (15) Partnership: 39 (42) India need 172 runs to win in 38 overs Abrar Ahmed comes into the attack. Ball 6- Kohli takes a single to long on Ball 5- Gill takes a single to long on Ball 4- Dot ball Ball 3- Gill defends the ball on front foot Ball 2- Gill plays the ball back to bowler. No run Ball 1- Kohli takes a single to cover7:43 PMIND vs PAK LIVE SCORE UPDATES: India 67 for 1. HBot is currently down due to some bug with Magick(dot)NET that's causing CPU/memory leaks.

Eternum-0 7 5 - Walkthrough-Rev-1 4 1

Blue = ButtonBrightnessOff; } TraktorX1MK2.controller.setOutput(group, padKey + "R", red, false); TraktorX1MK2.controller.setOutput(group, padKey + "G", green, false); TraktorX1MK2.controller.setOutput(group, padKey + "B", blue, !TraktorX1MK2.batchingLEDUpdate); }; TraktorX1MK2.outputHotcueCallback = function (value, group, key) { var hotcueNumber = key.charAt(7); var color; if (engine.getValue(group, "hotcue_" + hotcueNumber + "_status")) { color = colorCodeToObject(engine.getValue(group, "hotcue_" + hotcueNumber + "_color")); // hotcue_X_color reports red, green, and blue on a 0-255 scale, but the controller LEDs // only support values 0 - 127. color.red /= 2; color.green /= 2; color.blue /= 2; } else { color = { red: 0, green: 0, blue: 0 }; } TraktorX1MK2.sendPadColor(group, hotcueNumber, color); }; TraktorX1MK2.displayCharDigit = function (group, charPos, character) { // charPost is 0 or 1 for first or second character on the display // the display is placed like this: // o -- 4 -- // | | // 5 3 // | | // -- 1 -- // | | // 6 2 // | | // -- 7 -- // Where the numbers respresent each segment of the display // and the dot before it is 0 (but this is dealt with in displayCharDot) var numArray = { "": [], //empty 0: [2, 3, 4, 5, 6, 7], 1: [2, 3], 2: [1, 3, 4, 6, 7], 3: [1, 2, 3, 4, 7], 4: [1, 2, 3, 5], 5: [4, 5, 1, 2, 7], 6: [4, 5, 1, 2, 6, 7], 7: [4, 3, 2], 8: [1, 2, 3, 4, 5, 6, 7], 9: [5, 4, 1, 3, 2, 7], // Add a few special characters "h": [5, 1, 6, 2], "n": [6, 1, 2], "o": [6, 1, 2, 7], "-": [1], "b": [5, 6, 7, 2, 1], "c": [1, 6, 7], "u": [6, 2, 7], }; for (var j = 0; j 8; j++) { var seg = 8 * charPos + j; var key = "!display_segment" + seg; TraktorX1MK2.controller.setOutput( group, key, (numArray[character].indexOf(j) > -1) * OutputBrightnessMax, // if it's in the array turn it on, off otherwise !TraktorX1MK2.batchingLEDUpdate); } }; TraktorX1MK2.displayCharDot = function (group, charPos, on) { var key = "!display_segment" + 8 * charPos; TraktorX1MK2.controller.setOutput(group, key,