Curvature of earth per mile
Author: s | 2025-04-24
What is the Curvature of the Earth Per Mile? Understanding Earth’s Shape. Defining Curvature; The Impact of Earth’s Radius; Calculating Curvature. Using the Pythagorean If the Earth were flat, we would expect a curvature rate of zero inches per mile. As it is, the Earth is not flat, and it's curvature rate is 8 inches per mile. 63,360 inches are in a mile, and
Curvature Of The Earth Per Mile
MathTrigonometryTrigonometry questions and answersTwo ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.) Your solution’s ready to go!Our expert help has broken down your problem into an easy-to-learn solution you can count on.See AnswerQuestion: Two ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.) Show transcribed image textTranscribed image text: Two ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.) What is the Curvature of the Earth Per Mile? Understanding Earth’s Shape. Defining Curvature; The Impact of Earth’s Radius; Calculating Curvature. Using the Pythagorean If the Earth were flat, we would expect a curvature rate of zero inches per mile. As it is, the Earth is not flat, and it's curvature rate is 8 inches per mile. 63,360 inches are in a mile, and (3956.5467 miles) you get: 8.006982…For measurements along Earth's Polar radius (3949.9028 miles) you get: 8.020451…You can just see someone thinking.. "meh, 8 inches is in there somewhere". Why 8" per mile squared is wrongNow we can compare our better formula with this [8"×d²] estimation formula, I'll compare for Earth radius of 3959 miles: Earth Radius 3959 Distance (miles) Actual Drop (miles) Estimated Drop (miles) ERROR (miles) 1 0.000126 0.000126 0.000000 10 0.012629 0.012626 0.000003 100 1.262744 1.262626 0.000118 1000 124.341891 126.262626 -1.920735 2000 476.502339 505.050505 -28.548166 3000 1008.260915 1136.363636 -128.102721 3959 1639.871493 1979.000126 -339.128633 4000 1668.937544 2020.202020 -351.264476 From this is it easy to see that [8"×d²] is somewhat accurate for distances up to about 100 miles and then it is absolutely terrible after that. And now we know why - they threw out all the little corrections in the Taylor series that keep it accurate in order to make a simple "rule" that was "good enough" for what they needed at the time.So my advice is to gently inform those using it that it's only fairly accurate to about 100 miles but don't fret a few inches here and there when discussing the 'curvature' of the Earth.The more important issue to address is... Why It's Even More Wrong Than ThatBut more importantly, this [8"×d²] formula only gives you this somewhat wrong value for Drop Height, when what we actually care about, almost universally, is the height of a distant object that would be obscured for an observer at some elevation (h₀). I derive the correct formula to use for (h₁) height hidden by curvature at some distance in my other blog post but here is the short version:Additional NotesThere are TWO other ways to potentially measure Drop Height.The first one (which is the most common mistake) would be toComments
MathTrigonometryTrigonometry questions and answersTwo ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.) Your solution’s ready to go!Our expert help has broken down your problem into an easy-to-learn solution you can count on.See AnswerQuestion: Two ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.) Show transcribed image textTranscribed image text: Two ships leave a port at the same time. The first ship sails on a bearing of 57 st 24 knots (nautical miles per hour and the second on a bearing of 147° at 22 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth) After 1.5 hours, the ships are approximately nautical miles apart. (Round to the nearest nautical mile as needed.)
2025-04-21(3956.5467 miles) you get: 8.006982…For measurements along Earth's Polar radius (3949.9028 miles) you get: 8.020451…You can just see someone thinking.. "meh, 8 inches is in there somewhere". Why 8" per mile squared is wrongNow we can compare our better formula with this [8"×d²] estimation formula, I'll compare for Earth radius of 3959 miles: Earth Radius 3959 Distance (miles) Actual Drop (miles) Estimated Drop (miles) ERROR (miles) 1 0.000126 0.000126 0.000000 10 0.012629 0.012626 0.000003 100 1.262744 1.262626 0.000118 1000 124.341891 126.262626 -1.920735 2000 476.502339 505.050505 -28.548166 3000 1008.260915 1136.363636 -128.102721 3959 1639.871493 1979.000126 -339.128633 4000 1668.937544 2020.202020 -351.264476 From this is it easy to see that [8"×d²] is somewhat accurate for distances up to about 100 miles and then it is absolutely terrible after that. And now we know why - they threw out all the little corrections in the Taylor series that keep it accurate in order to make a simple "rule" that was "good enough" for what they needed at the time.So my advice is to gently inform those using it that it's only fairly accurate to about 100 miles but don't fret a few inches here and there when discussing the 'curvature' of the Earth.The more important issue to address is... Why It's Even More Wrong Than ThatBut more importantly, this [8"×d²] formula only gives you this somewhat wrong value for Drop Height, when what we actually care about, almost universally, is the height of a distant object that would be obscured for an observer at some elevation (h₀). I derive the correct formula to use for (h₁) height hidden by curvature at some distance in my other blog post but here is the short version:Additional NotesThere are TWO other ways to potentially measure Drop Height.The first one (which is the most common mistake) would be to
2025-03-27The curvature of railroad tracks must be carefully engineered to allow the trains to transit as a safe speed whilst maintaining stability. This simple Railroad Curve Calculator allows you to calculate the degree of curve by entering the radius of the curve. Railroad Degree of Curve Calculator Enter Radius Railroad Curve Calculator Results Degree of Curve = This tutorial provides an introduction to the concept of the Railroad Curve Calculator, a tool used in engineering disciplines to calculate various parameters related to railroad curves. The article covers interesting facts about railroad curves, explains the formula used in the calculator, provides real-life examples of its applications, and includes detailed instructions for its usage. Interesting Facts about Railroad Curves Railroad curves play a crucial role in the design and construction of railways. Here are some interesting facts about railroad curves: The curvature of a railroad curve is measured in degrees per unit length, typically expressed as degrees per 100 feet or degrees per 100 meters. The sharper the curve, the higher the degree of curvature. Curvature is denoted by the symbol "C." Curvature affects the speed at which trains can safely travel around a curve. Higher curvature requires reduced speeds to prevent derailments. Railroad curves are often banked or superelevated to counteract the centrifugal force acting on trains as they navigate the curve. This helps to maintain stability and passenger comfort. Formula for Railroad Curve Calculator The Railroad Curve Calculator employs a formula based on the degree of curvature (C), the length of curve (L), and the radius of the curve (R). The formula is as follows: R = 5729.57795 / C L = R × 2 × π × (C / 360) Where: R is the radius of the curve. C is the degree of curvature. L is the length of
2025-03-25YesHomeCollection of tools to know and work with solar energy. Calculation of: sun position, latitude longitude coordinates, photovoltaic systems, emissions CO2. Photovoltaic paybackEconomic analysis of a photovoltaic system, with the determination of payback and chart. Sun PositionCalculation of sun’s position in the sky for each location on the earth at any time of day. Azimuth, sunrise sunset noon, daylight and graphs of the solar path. 2 Emissions">2 Emissions" width="100" height="100"> 2 Emissions">CO2 EmissionsMeasure emissiones of CO2 per kWh of energy produced, or emissions in g/km of your car. Enter the kWh produced by a year the nation’s electricity mix.2 Emissions"> 2 Emissions" width="30" height="10"> Unit of measure converterUnits measurement conversion: Length Area Volume Mass Force Power Energy Time Temperature Angle Speed Flow Acceleration Pressure Electrical Luminance ... Measure on MapMeasure on google map: latitude longitude coordinates DD DMS, address and location, distance (km, meters, mile, foot), area, poliline, circle, perimeter. DistanceDrag the marker on map to calculate distance (km, meters, mile, foot) and bearing angle of direction on google map, between two points of the earth. Calculation of average speed or time spent. Coordinates conversionConversions latitude longitude geographic coordinates, in all formats: decimal, sexagesimal, GPS DD DM DMS degrees minutes seconds, search by clicking on map. Full interactive mapTools on interactive map, sun path, sun rays, shadow, area, distance, polyline path, coordinates. Sunrise Sunset CalendarCalendar of sunrise sunset noon daylight of the sun at any location on the planet for an entire year. The table shows the time and azimuth
2025-04-02Back on yourself? These are the questions we're talking about when we refer to the geometry of the universe.Shape of the universe FAQsHow do scientists know the shape of the universe?We measure the geometry of the universe by measuring the average density of matter in space and comparing it to a critical density, which dictates the curvature of space.What shapes the universe?The gravitational effect of matter can affect the curvature of space, per general relativity, but quantum effects during the Big Bang also influenced the shape of the universe.Is the universe a sphere or flat? Whether the universe is flat or curved like a sphere (closed) depends on how close the density of matter is to the critical density. Measurements show that the density is almost a match for the critical density, which indicates a flat universe.What is the true shape of the universe? A flat universe has Euclidean geometry, and the simplest shape it can adopt is that of a sheet. There are also other, more complex shapes that a flat universe could have, such as a "3-torus."How to measure the shape of the universeThe geometry of the universe is determined by the density of matter within the universe. Albert Einstein's theory of general relativity describes how matter can curve space, so the matter's density can control the curvature and geometry of space on the largest scales.The key value is the "critical density," which is denoted by the Greek letter omega (𝛀). The universe has the critical density if it contains, on average, six hydrogen atoms per cubic meter. But matter is not spread evenly throughout the universe. We know this because we see it concentrated within galaxies and absent in the gaps between galaxies. However, when we talk about the density of matter in the universe, we're imagining spreading every atom in the universe (three-quarters of which are hydrogen) evenly across space.There's also dark matter, which we can infer only from its gravitational effects, but we know it must account for about 85% of all matter in the universe. Having a handle on the amount of dark matter
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